625-9p^2=0

Solution for 625-9p^2=0 equation:

625-9p^2=0

a = -9; b = 0; c = +625;
Δ = b2-4ac
Δ = 02-4·(-9)·625
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*-9}=\frac{-150}{-18}
=8+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*-9}=\frac{150}{-18}
=-8+1/3
$